Question

如果│A+1│+(B-2)的平方=0,求(A+B)的2003次方+A的2004次方的值

Answer 1

因为 │A+1│+(B-2)的平方=0

所以 A+1=0 B-2=0

所以 A=-1 B=2

所以(A+B)的2003次方+A的2004次方=2

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