Question

已知a3m=3 b3n=2求（a2m）3+（bn）3-a2m*bn*a4m*b2n（a的2m次方的3次方+b的n次方的3

Answer 1

a^3m=3,b^3n=2

原式=a^(2m)^3+(b^n)^3-a^(2m)*b^n*a^4m*b^3n

=(a^3m)^2+b^(3n)-a^(6m)*b^(4n)

=3^2+2-[a^(3m)]^2*(b^3n)^(4/3)

=11-9×2^(4/3)

题目如果是：a^(2m)^3+(b^n)^3-a^(2m)*b^n*a^4m*b^2n

则原式=(a^3m)^2+b^(3n)-a^(6m)*b^(3n)

=9+2-9×2

=11-18

=-7