x³y-xy³/(x³-2x²y+y²x)
=xy(x²-y²)/[x(x²-2xy+y²)]
=xy(x+y)(x-y)/[x(x-y)²]
=y(x+y)/(x-y)
x³-16x/(x²-8x+16)
=x(x²-16)/(x-4)²
=x(x+4)(x-4)/(x-4)²
=x(x+4)/(x-4) 是吧
数学分式约分约分这个分式：x³y-xy³/x³-2x²y+y²x（有步
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