Question

已知|x-8y|+2(4y-1)^2+3|8z-3x|=0,求x+y+z的值

Answer 1

因为|x-8y|≥0,

(4y-1)^2≥0,

|8z-3x|≥0.

又因为|x-8y|+2(4y-1)^2+3|8z-3x|=0.

所以|x-8y|=0,

(4y-1)^2=0,

|8z-3x|=0.

即x-8y=0,

4y-1=0,

8z-3x=0

解得x=2

y=1/4

当 x=2

y=1/4 z=3/4时

x+y+z=2+1/4+3/4

=3