Question

因式分解：-2y^2-6+2xy+3x-7y

Answer 1

x^2+xy-2y^2-x+7y-6

=(x^2-xy+2x)+(2xy-2y^2+4y)-(3x-3y+6)

=x(x-y+2)+2y(x-y+2)-3(x-y+2)

=(x-y+2)(x+2y-3)