-1/2 ln(1-2u^3) = lnx+lnc
ln(1-2u^3) + 2 lnx = C1
ln[ (1-2u³) x² ] = C1
=> ln( x² - 2y³/x ) = C1
=> x² - 2y³/x = C
即:x³ - 2y³ = C x
-1/2 ln(1-2u^3) = lnx+lnc
ln(1-2u^3) + 2 lnx = C1
ln[ (1-2u³) x² ] = C1
=> ln( x² - 2y³/x ) = C1
=> x² - 2y³/x = C
即:x³ - 2y³ = C x