1.∵已知a,b,x,y是有理数,且|x-a|+(y+b)²=0
∴|x-a|=0
(y+b)²=0
∴x=a
y=-b
∴﹙a²+ay-bx+b²﹚/﹙x+y﹚÷﹙a²+ax+by-b²﹚/﹙a+b﹚
=﹙a-b﹚/﹙2﹤a-b﹥﹚
=1/2
=0.5
2∵.x²+y²=5,xy=2,﹙ x+y﹚²=5+4=9 x+y=±3
∴1/﹙1/x+1/y﹚
=1/[﹙x+y﹚/﹙xy﹚]
=﹙xy﹚/﹙x+y﹚
=2/﹙±3﹚
=±2/3
1.∵已知a,b,x,y是有理数,且|x-a|+(y+b)²=0
∴|x-a|=0
(y+b)²=0
∴x=a
y=-b
∴﹙a²+ay-bx+b²﹚/﹙x+y﹚÷﹙a²+ax+by-b²﹚/﹙a+b﹚
=﹙a-b﹚/﹙2﹤a-b﹥﹚
=1/2
=0.5
2∵.x²+y²=5,xy=2,﹙ x+y﹚²=5+4=9 x+y=±3
∴1/﹙1/x+1/y﹚
=1/[﹙x+y﹚/﹙xy﹚]
=﹙xy﹚/﹙x+y﹚
=2/﹙±3﹚
=±2/3