设等差数列{an}的首项为公差为d
Sn=a1+a2+……+an
S2n-Sn=an+1 +an+2 +……+a2n
S3n-S2n=a2n+1 +a2n+2 +……+a3n
(S2n-Sn)-Sn=(an-a1)+(an+1-a2)+……+(a2n-an)=n(a2n-an)=n*nd
同理可得,
(S3n-S2n)-(S2n-Sn)=n(a3n-2n)=n*nd
所以(S2n-Sn)-Sn=(S3n-S2n)-(S2n-Sn),
即Sn,S2n-Sn,S3n-S2n是等差数列
设等差数列{an}的首项为公差为d
Sn=a1+a2+……+an
S2n-Sn=an+1 +an+2 +……+a2n
S3n-S2n=a2n+1 +a2n+2 +……+a3n
(S2n-Sn)-Sn=(an-a1)+(an+1-a2)+……+(a2n-an)=n(a2n-an)=n*nd
同理可得,
(S3n-S2n)-(S2n-Sn)=n(a3n-2n)=n*nd
所以(S2n-Sn)-Sn=(S3n-S2n)-(S2n-Sn),
即Sn,S2n-Sn,S3n-S2n是等差数列