Question

（2x-1)(3x-2)=2 t(t-4根号3)=-12 (3x-5)(x-1)=3 2x(x-1)=x-1 -5x^2

Answer 1

（2x-1)(3x-2)=2 6x²-7x+2=26x²-7x=0x(6x-7)=0x=0或x=7/6t(t-4根号3)=-12 t²-4√3t+12=0(t-2√3)²=0t1=t2=2√3(3x-5)(x-1)=3 3x²-8x+5=33x²-8x+2=0x=(8±2√10)/6=(4±√10)/32x(x-1)...