Question

ab(a+b)^2-(a+b)^2+1.因式分解怎么解?

Answer 1

ab(a+b)^2-(a+b)^2+1

=a(a+b)*b(a+b)-(a+b)(a+b)+1

=a(a+b)*b(a+b)-a(a+b)-b(a+b)+1

=[a(a+b)-1][b(a+b)-1]