设a>b>1,y1=sin[(b+1)/(a+1)],y2=sin(b/a),y3=sin[(b-1)/(a-1)],则
1个回答
虽然因为a>b>1,则1>(b+1)/(a+1)>b/a>(b-1)/(a-1)>0
而y=sinx在(0,1)上单调递增
所以y1>y2>y3
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