Question

若复数z=（1+i）／（1-i）+m(1-i)为纯虚数,求实数m的值

Answer 1

(1+i)/(1-i)+m(1-i)

=i+m-mi

=m+(1-m)i

复数z为纯虚数,所以其实部为0,虚部不为0.

即m=0,1-m≠0,求得m的值为0