x=3-y-z,从而3-y-z+2y+3z=3+y+2z=6 2x+y+2z=6-2y-2z+y+2z=6-y= 5 y=1; x=2-z
有3+y+2z=6得4+2z=6 z=1 从而x=1
即x=y=z=1
x+y+z=3(1) x+2y+3z=6(2) 2x+y+2z=5(3)
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相关问题
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方程 ｛3x+3y+z=6 ｛x-y-2z=-1 ｛x+2y-z=5
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证明：（y+z-2x）3+（z+x-2y）3+（x+y-2z）3=3（y+z-2x）（z+x-2y）（x+y-2z）．
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(1)3x+4y=15 2y-z=2 x+2z=9 (2) x+y+z=8 2x+3y-z=6 3x-y+z=8 (3)
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2x+y+3z=5 3x-2y-z=6 4x-3y+2z=4
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x-y+z=5 2x+3y+z=-2 x-2y-z=3
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(1)2X+4Y+3Z=93X-2Y+5Z=115X-6Y+7Z=13(2)X:Y=3:2Y:Z=5:4X+Y+Z=66