x^2 +bx +c -x = 0
x^2 +(b-1)x +c = 0
(x-2)(x-5)=0
x^2 -7x +10 =0
b = 8 ,c = 10
N:
(x^2-7x+10)^2 -7(x^2-7x+10) +10 - x =0
x^2 -7x +10 = 2 或 x^2 -7x +10 = 5
x^2 -7x +8 = 0 或 x^2 -7x +5 = 0
解得:
x = (7+根号17)/2 或 x = (7-根号17)/2
或
x = (7+根号29)/2 或 x = (7-根号29)/2
所以
N:有四个元素.