原式=(x²-xy)/(x²-2xy+y²)-(x+y)/(x-y)
=x(x-y)/(x-y)²-(x+y)/(x-y)
=x/(x-y)-(x+y)/(x-y)
=(x-x-y)/(x-y)
=-y/(x-y)
x/y=3/5;
原式=-1/(x/y-1)=-1/(3/5-1)=5/2;
如果本题有什么不明白可以追问,
原式=(x²-xy)/(x²-2xy+y²)-(x+y)/(x-y)
=x(x-y)/(x-y)²-(x+y)/(x-y)
=x/(x-y)-(x+y)/(x-y)
=(x-x-y)/(x-y)
=-y/(x-y)
x/y=3/5;
原式=-1/(x/y-1)=-1/(3/5-1)=5/2;
如果本题有什么不明白可以追问,