2(3x-1)(4x-1)(6x+1)(12x+1)=3
2个回答
原式=[2(3x-1)(4x-1)][(6x+1)(12x+1)]=3*1
可推得,2(3x-1)(4x-1)=1
(6x+1)(12x+1)=3
经计算,两式公共解为1/12
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