Question

a,b互为相反数,c,d互为倒数,丨x丨=2,试求x^2-(a+b+cd)x+(a+b)^2012+(-cd)^2011

Answer 1

a,b互为相反数,c,d互为倒数,丨x丨=2,

所以a+b=0 cd=1 x=±2

x^2-(a+b+cd)x+(a+b)^2012+(-cd)^2011

=4-（0+1）x+0-1

=3-x

当x=2时,上式=3-2=1

当x= -2时,上式=3+2=5