(8/1+24/1+48/1+80/1+120/1+168/1+224/1)X16
1个回答
=(1+3+6+10+15+21+28)/2
=84/2
=42
相关问题
(1/8+1/24+1/48+1/80+1/20+1/168+1/224+1/288)x128=?
42x(8/1+24/1+48/1+80/1+120/1+168/1)=?
(1/8+1/24+1/48+1/80+1/120+1/168)*56
(1/8+1/24+1/48+1/80+1/120+1/168)简便计算
42×([1/8]+[1/24]+[1/48]+[1/80]+[1/120]+[1/168])
求(1/8+1/24+1/48+1/80+1/120+1/168+1/224+1/288)*128,请问可以套用哪种列项
1+3又1/8+5又1/24+7又1/48+9又1/80+11又1/120+13又1/168+15又1/224+17又1
121 *3/4-3/8*40-0.75 (1/8+1/24+1/48+1/80+1/120+1/168)*56
计算11/8+1/24+1/48+1/80+1/120
解方程. 40%X=120 80%X-60%X=1.2 6X+48=168 X+20%X=24 X-[x/5]=16 1