Question

有个方程的规律是：x+x分之2=a+a分之2解这个方程x-1分之x的平方-x+2=a+a-1分之2

Answer 1

应该是

x+2/x=a+2/a

则x=a,x=2/a

(x²-x+2)/(x-1)=a+2/(a-1)

x(x-1)/(x-1)+2/(x-1)=a+2/(a-1)

x+2/(x-1)=a+2/(a-1)

两边减去1

(x-1)+2/(x-1)=(a-1)+2/(a-1)

所以x-1=a-1,x-1=2/(a-1)

x=a,x=1+2/(a-1)

即x=a,x=(a+1)/(a-1)