化简 (1+cos20)/2sin20 -sin10(cot5-tan5) 答案等于根3/2

2个回答

  • (1+cos20)/2sin20 -sin10(cot5-tan5)

    =[1+ 2 (cos10)^2-1]/4sin10 cos10 - 2sin5 cos 5 (cos5/sin5 - sin5/cos5)

    =cos10/2sin10 - 2[(cos5)^2 - (sin5)^2]

    =cos10/2sin10- 2 cos10

    =(cot10 -4 cos10)/2

    =(cos10-4sin10 cos10)/2sin10

    =(sin80-2sin20)/2sin10

    =(sin80-sin20-sin20)/2sin10

    =(2cos50sin30 -sin20)/2sin10

    =(cos50 - sin 20)/2sin10

    =(sin40 - sin20)/2sin10

    =2cos30sin10/2sin10

    =cos30

    =根3/2