f(x)=sin(2x-π/6),π/4≤x≤π/2,求f(x)的值域
1个回答
π/4≤x≤π/2 π/2≤2x≤π π/3≤2x-π/6≤5π/6
f(x)=sin(2x-π/6)的域是[1/2,1]
相关问题
已知函数f (x)=2sin(x+π/6)-2cosx,x∈【π/2,π】,求:函数f(x)的值域
求函数f(x)=2sin(2x-π/3)的值域(6/π
已知函数f(x)=根号2sin(2x+6π).x∈[π/12,π/3].求f(x)的值域.
函数f(x)=2sin(x+π/4)sin(x-π/4)+sin2x的值域
求函数f(x)=sin(2x+π/3)+2cos^2(2x+π/3),x∈(-π/3,π/6]的值域
f(x)=2sin(2x+π/6),若x属于[0,π/2] ,求函数f(x)的值域
f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)的对称轴方程,在〖—π/12.π/2〗的值域
化简f(x)=2sin(x+ π/2 )sin(x+ π/3)+cos(5π/6),(x属于R),并求函数f(x)的值域
三角函数问题:已知函数f(x)=根号2sin(2x+π/6).x∈[π/12,π/3].求f(x)的值域.
1.求函数f(x)=sin(-x+π/3)在[π/6,/2π]上的值域