Question

若分式2x+3分之x-2值为正x的范围

Answer 1

1、值为0.

即x-2=0且2x+3≠0,解得x=2.

2、值为正.

即x-2＞0,2x+3＞0,或者x-2＜0,2x+3＜0,解得x＞2或x＜-1.5

3、值为负.

即x-2＞0,2x+3＜0,或者x-2＜0,2x+3＞0,解得-1.5＜x＜2

4、值为1.

即x-2=2x+3且2x+3≠0,解得x=-5