AC=根号(AB^2+AB^2)=根号(7^2+24^2)=25
设距离是h
连结AP、BP、CP
S△ABC
=S△APB+S△BPC+S△CPA
=AB·h/2+BC·h/2+AC·h/2
=(AB+BC+AC)·h/2
=(7+24+25)h/2
=28h
又
S△ABC
=AB·BC/2
=7*24/2
=84
所以
28h=84
h=3
AC=根号(AB^2+AB^2)=根号(7^2+24^2)=25
设距离是h
连结AP、BP、CP
S△ABC
=S△APB+S△BPC+S△CPA
=AB·h/2+BC·h/2+AC·h/2
=(AB+BC+AC)·h/2
=(7+24+25)h/2
=28h
又
S△ABC
=AB·BC/2
=7*24/2
=84
所以
28h=84
h=3