答案为x=2,y=3,z=1; 解答过程为：1式与3式相加可得5x+5y=25,算出x+y=5,代入2式得z=1,再把z=1代入可得x=2,y=3；要采纳哦!
{3x+2y+z=13 x+y+2z=7 2x+3y-z=12,求x,y,z
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1.x+y+z=21,x-y=1,2x+z-y=13.2.3x+2y+z=13,x+y+2z=7 ,2z+3y-z=12
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{3x+2y+z=13 {x+y+z=7 {2x+3y-z=12
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证明：（y+z-2x）3+（z+x-2y）3+（x+y-2z）3=3（y+z-2x）（z+x-2y）（x+y-2z）．
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