1.证明:
右式=XY+(X⊕Y)Z
=XY+XY'Z+X'YZ
=X(Y+Y'Z)+X'YZ
=X(Y+Z)+X'YZ
=XY+XZ+X'YZ
=XY+Z(X+X'Y)
=XY+Z(X+Y)
=XY+XZ+YZ
=左式
2.如下图,绿色为函数项,橙色为约束项;红色为答案项
F=A+B'+D'
1.证明:
右式=XY+(X⊕Y)Z
=XY+XY'Z+X'YZ
=X(Y+Y'Z)+X'YZ
=X(Y+Z)+X'YZ
=XY+XZ+X'YZ
=XY+Z(X+X'Y)
=XY+Z(X+Y)
=XY+XZ+YZ
=左式
2.如下图,绿色为函数项,橙色为约束项;红色为答案项
F=A+B'+D'