已知a(y-z)+b(z-x)+c(x-y)=0,求证:(x-y)/(a-b)=(y-z)/(b-c)=(z-x)/(c
2个回答
a(y-z)+b(z-x)+c(x-y)=0
可化简成
a(y-z)+b((z-y)+(y-x))+c(x-y)=0
分解因式可得前边部分,然后再分解y-z或者x-y即可
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