h=3.43×10^5 m,R=6.371×10^6 m
设组合体质量为m,地球质量为M,根据万有引力定律有
GMm/(R+h)^2=mw^2*(R+h)=m(2π/T)^2*(R+h) ①
而近地面有
GMm/R^2=mg ②
①/②得
[R/(R+h)]^2=(2π/T)^2*(R+h) /g
解得周期为
T=2π/√[R^2*g/(R+h)^3]=5.4788*10^3 (s)=91.3133(min)
h=3.43×10^5 m,R=6.371×10^6 m
设组合体质量为m,地球质量为M,根据万有引力定律有
GMm/(R+h)^2=mw^2*(R+h)=m(2π/T)^2*(R+h) ①
而近地面有
GMm/R^2=mg ②
①/②得
[R/(R+h)]^2=(2π/T)^2*(R+h) /g
解得周期为
T=2π/√[R^2*g/(R+h)^3]=5.4788*10^3 (s)=91.3133(min)