原式=[3/(x-1) -x-1]÷ (x-2)/(x^2-2x+1)
=[(3-x^2+1)/(x-1)]*(x-1)^2/(x-2)
=-(x+2)(x-1)
=-(x^2+x-2),
又因为x^2-2x=x(x-2)=0,解得x=0或x=2,代入可得原式=2或0
原式=[3/(x-1) -x-1]÷ (x-2)/(x^2-2x+1)
=[(3-x^2+1)/(x-1)]*(x-1)^2/(x-2)
=-(x+2)(x-1)
=-(x^2+x-2),
又因为x^2-2x=x(x-2)=0,解得x=0或x=2,代入可得原式=2或0