-9/5a的1/2乘以b的3/2
(5/6)a^(1/3)*b(-2)*[-3a^(-1/2)b^(-1)]除以[4a^(2/3)*b(-3)]^1/2×
1个回答
相关问题
-
(a^4/3-8a^1/3b)/(a^2/3+2(ab)^1/3+4b^2/3)除以(1-2(b/a)^1/3)×a^1
-
4a2/3次方×b-1/3次方除以(-3/2a-1/3×b-1/3)
-
化简(a^2/3b^1/2)(-3a^1/6b^1/3)除以(1/3a^1/6b5/6)的结果是
-
(a^2/3*b^1/2)(-3a^1/2b^1/3)/(1/3a^1/6*b^5/6)
-
[6a^2b^2+?]除以?=3a+b-1
-
计算[2a^(2/3)b^(1/2)][-6a^(1/2)b^(1/3)]÷[-3a^(1/6)b^(5/6)]
-
已知:1/2×2=1/2+2,2/3×3=2/3+3,3/4×4=3/4+4,...若b/a×10=b/a+10(a、b
-
化简【(a^2/3)(b^1/2)(-3a^1/2)(b^1/3)】÷【1/3(a^1/6)(b^5/6)】
-
1/3(a-b)^2*6(b-a)^3*5/2(b-a)^4,
-
6a²-5a(-a+2b+1)+4a(-3a-5/2b-3/4),其中a=-1,b=1/20.