x²+y²-x+y-k=0
(x²-x+1/4)+(y²+y+1/4)-k-1/2=0
(x-1/2)²+(y+1/2)²=k+1/2
因为圆的基本方程为(x―a)²+(y―b)²=r²
因此本题中圆的半径为√(k+1/2)
在一般式中,x的系数是D,y的系数是E,常数项是F
D=-1 E=1 F=-k
r=1/2√D²+E²-4F
=1/2√(1+1+4k)
=1/2√(2+4k)
=1/2√[4×(1/2+k)]
=1/2×2√(k+1/2)
=√(k+1/2)
x²+y²-x+y-k=0
(x²-x+1/4)+(y²+y+1/4)-k-1/2=0
(x-1/2)²+(y+1/2)²=k+1/2
因为圆的基本方程为(x―a)²+(y―b)²=r²
因此本题中圆的半径为√(k+1/2)
在一般式中,x的系数是D,y的系数是E,常数项是F
D=-1 E=1 F=-k
r=1/2√D²+E²-4F
=1/2√(1+1+4k)
=1/2√(2+4k)
=1/2√[4×(1/2+k)]
=1/2×2√(k+1/2)
=√(k+1/2)