Question

(a-b/a+b)2x3a+3b/2a-2b-a2-b2/a2除以b分之a

Answer 1

(a-b/a+b)2x3a+3b/2a-2b-a2-b2/a2除以b分之a

=[2(a-b)/(a+b) * (3a+3b)/(2a-2b)-(a2-b2)/a2 ]÷a/b

=[2(a-b)/(a+b)*3(a+b)/2(a-b)-(a2-b2)/a2 ]÷a/b

=[3-(a-b)/a ]÷a/b

=[(3a-(a-b))/a]÷a/b

=(b+2a)/a *b/a

=(b^2+2ab)/a^2

=(b/a)^2+2b/a