若3^15a=5^5b=15^3c,则5ab-bc-3ac=?

2个回答

  • 先假设3^15a=5^5b=15^3c=x

    对各等式取以x为底的对数,

    logx 3^15a=logx 5^5b=logx 15^3c=logx x

    15a*logx 3=5b*logx 5=3c*logx 15=1

    a=1/(15*logx 3)

    b=1/(5*logx 5)

    c=1/(3*logx 15)

    5ab-bc-3ac=5*1/(15*logx 3)*1/(5*logx 5)-1/(5*logx 5)*1/(3*logx 15)-3*1/(15*logx 3)*1/(3*logx 15)=1/15(1/(logx 3*logx 5)-1/(logx 5*logx 15)-1/(logx 3*logx 15))

    =1/15(1/(logx 3*logx 5)-(logx 3+logx 5)/(logx 3*logx 5*logx 15))

    =1/15(1/(logx 3*logx 5)-logx 15/(logx 3*logx 5*logx 15))

    =1/15(1/(logx 3*logx 5)-1/(logx 3*logx 5))

    =0