设x=(log1/2底1/3)^-1+(log1/5底1/3)^-1,若x属于(k,k+1),则k
1个回答
x=1/log(1/2)(1/3)+1/log(1/5)(1/3)
=log3(2)+log3(5)
=log3(10)
log3(9)
相关问题
若k属于R,解不等式:log2(1+x/1+x)>log2(1+x/k)
若k属于R,解不等式:log2[(1+x)/(1-x)]>log2[(1+x)/k]
设a=1/(log下标4 3)+1/(log下标7 3),且a∈(k,k+1),k∈z,则k
设f(k)是满足不等式log(2)x+log(2)3*2^(k-1)-x>=2k-1的自然数x的个数.(1)求f(k)的
设f(k)是满足不等式log 2 x+log 2 (3•2 k-1 -x)≥2k-1(k∈N*)的正整数x的个数.
设x0是方程4-x^2=log2底 x的一个解 若x0∈(k,k+1) k∈Z求K
设f(k)满足不等式log2x+log2(3*2^(k-1)-x)>=2k-1的自然数的个数,求f(k)的
设函数f(x)=log1/3 kx^2+(k+2)x+(k+2) (k∈R)
若函数f(x)=log3x+x-3的零点所在的区间是(k,k+1),则整数k=
设f(x)=x2-x+k,log2f(a)=2,f(log2a)=k,(a≠1)