For line L1 passes through the point (3,6,1) and is parallel to 2i+3j-k,
suppose L1:2i+3j-k=c ,
then 2*3+2*6-1=c ; c=17,
so L1:2i+3j-k=17.
suppose L2 :i-2j+k=c1,
so L2 :i-2j+k=9.
a) For the acute angle between L1 and L2 equals the acute angle between 2i+3j-k=0 (K1)and i-2j+k=0(K2),
then tanA=|K1-K2|/|1+K1K2|=sqr(42)/4,
so A=Arctan【sqr(42)/4】.
b) For the point B(5,a,b)lies on the line L2,
then 5-2a+b=9,
so 2a-b=-4.