初一数学,要详细过程,谢谢.速度ok么

1个回答

  • 1、a/b=2

    ∴a=2b

    a平方-ab+b平方/a平方+b平方=(4b^2-2b^2+b^2)/(4b^2+b^2)=(3b^2)/5b^2=3/5

    2 (1)=(a-2)/b(a-2)=1/b

    (2)=(x+3)(x-3)/(x-3)^2=(x+3)/(x-3)

    (3)=(x+7)(x-7)/(x-7)=x+7

    (4)=[(m+n)+2(m-n)][(m+n)-2(m-n)]/(3n-m)

    =(m+n+3m-2n)(m+n-2m+2n)/(3n-m)=(4m-n)(3n-m)/(3n-m)=4m-n

    (5)=x(3x-6y+1)/(3x-6y+1)=x

    (6)=(a-2b-2)^2/(a-2b-2)=a-2b-2

    (7)=3ab(2a+3b)/(3b+2a)=3ab

    (8)=(x+1/3)(x-1/3)/[3(x-1/3)]=(x+1/3)/3=x/3+1/9

    (9)=(2x-1)^2/(1-2x)=-(2x-1)^2/(2x-1)=1-2x

    (10)=(3x+y+3x-y)(3x+y-3x+y)/2(2x-y)=6x*2y/2(2x-y)=6xy/(2x-y)