设 ∠AOC=α,
则 sinα=4/5 ,cosα=3/5 ,
设 点D是圆O与y轴正半轴的交点,
∵ △AOB为正三角形,
∴ ∠BOD=α-30°,
∴ sin(α-30°)
=sinα·cos30°-cosα·sin30°
=(4/5)·[(√3)/2]-(3/5)·(1/2)
=(4√3)/10-3/10
=(4√3-3)/10 ;
cos(α-30°)
=cosα·cos30°+ sinα·sin30°
=(3/5)·[(√3)/2]+(4/5)·(1/2)
=(3√3)/10+4/10
=(3√3+4)/10 ;
∴ B点的坐标[(4√3-3)/10 ,(3√3+4)/10] .