Question

已知x、y互为相反数,且(x+1)^2+(y+1)^2=4,求y和x的值

Answer 1

x、y互为相反数

x+y=0

y=-x

(x+1)^2+(y+1)^2=4

(x+1)^2+(-x+1)^2=4

x^2+2x+1+x^2-2x+1=4

2x^2=2

x^2=1

x=1 或 x=-1

y=-1 或 y=1