Question

以知a的立方+2a=-2,则3a的六次方+12a的四次方-a的三次方+12a的平方-2a-4=

Answer 1

a^3+2a=-2

3a^6+12a^4-a^3+12a^2-2a-4

=(3a^6+12a^4+12a^2)-(a^3+2a)-4

=3(a^6+4a^4+4a^2)-(a^3+2a)-4

=3(a^3+2a)^2-(a^3+2a)-4

=3(-2)^2-(-2)-4

=10