甲乙两根木棒插在水池中,两根木棒的和是230cm,甲棒有5分之3露在水面上,乙棒有4分之1露在水面上,水深多少?

1个回答

  • 水深={[(1-3/5)X230]/[(1-1/4)+(1-3/5)]}X(1-1/4)

    ={[(2/5)X230]/[(3/4)+(2/5)]}X(3/4)

    ={[92]/[(15/20)+(8/20)]}X(3/4)

    ={[92]/[23/20]}X(3/4)

    ={80}X(3/4)

    =60(cm)

    或:

    水深={[(1-1/4)X230]/[(1-1/4)+(1-3/5)]}X(1-3/5)

    ={[(3/4)X230]/[(3/4)+(2/5)]}X(2/5)

    ={[172.5]/[(15/20)+(8/20)]}X(2/5)

    ={[172.5]/[23/20]}X(2/5)

    ={150}X(2/5)

    =60(cm)

    水深60cm

相关问题