几个定积分,1.∫√(1-x)√(1+x)dx 积分范围[-1,1]2.∫x^3*e^(x^2)dx [-1,1]3.∫

2个回答

  • 1.∫(- 1→1) √(1 - x)√(1 + x) dx

    = ∫(- 1→1) √(1 - x²) dx

    = 1/2 * π(1)²

    = π/2

    2.∫(- 1→1) x³e^(x²) dx

    = 0

    3.∫(0→1) √(x² + 1) dx,x = tanz,dx = sec²z dz

    = ∫(0→π/4) √(tan²z + 1) * sec²z dz

    = ∫(0→π/4) sec³z dz

    = (1/2)secztanz + (1/2)ln(secz + tanz) |(0→π/4)

    = (1/2)(√2)(1) + (1/2)ln(√2 + 1)

    = 1/√2 + (1/2)ln(1 + √2)

    4.∫(0→π) 1/(2 - cosx) dx

    = ∫(0→π) 1/[2sin²(x/2) + 2cos²(x/2) - cos²(x/2) + sin²(x/2)] dx

    = ∫(0→π) 1/[3sin²(x/2) + cos²(x/2)] dx

    = 2∫(0→π) 1/[1 + 3tan²(x/2)] d[tan(x/2)]

    = (2/√3)arctan[√3tan(x/2)] |(0→π)

    = (2/√3)(π/2)

    = π/√3

    5.∫(-∞→+∞) e^(- x²/2) dx

    = ∫(-∞→+∞) e^(- (x/√2)²) dx

    u = x/√2,dx = √2 du

    = √2∫(-∞→+∞) e^(- u²) du

    = √2 * √π

    = √(2π)

    你自己说了不要解释的,别又问长问短了.