1/√2+1/(√3+√2)-2/(√3-1) √4ab/a√b-b√a 化简,..
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1/√2+1/(√3+√2)-2/(√3-1) =√2/2+√3-√2-√3-1=-√2/2-1
√4ab/a√b-b√a=√4a*b/ab-b√a=2√a/a-b√a=(2/a-b)√a
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