由一般的情况:
1/(a-2)a(a+2)
=1/4*(1/(a-2)a-1/a(a+2))
所以
原式=1/4*(1/1*3-1/3*5+1/3*5-1/5*7+...+1/99*101-1/101*103)
=1/4*(1/1*3-1/101*103)
=1/4*(1/3-1/101*103)
=2600/312209
由一般的情况:
1/(a-2)a(a+2)
=1/4*(1/(a-2)a-1/a(a+2))
所以
原式=1/4*(1/1*3-1/3*5+1/3*5-1/5*7+...+1/99*101-1/101*103)
=1/4*(1/1*3-1/101*103)
=1/4*(1/3-1/101*103)
=2600/312209