Question

用加减消元法解二元一次方程组：①[(x+y)/2]+[(x-y)/3]=5②[(x+y)/2]+[(x-y)/3]=-1

Answer 1

①[(x+y)/2]+[(x-y)/3]=5

②[(x+y)/2]+[(x-y)/3]=-1

①-②

(x-y)/3=6

x-y=18,x+y=2

相加

2x=20,x=10,则y=-8