1.原式=(5a-4b)(5a-4b-3a+2b)
=(5a-4b)(2a-2b)
=10a²-18ab+8b²
2.原式=(4x²-1)(4x²-1)
=16x^4-8x²+1
(5a-4b)^2-(5a-4b)(3a-2b) (2x-1)(2x+1)(4x^2-1)
2个回答
相关问题
-
x3-5x2+5x-4x5+1/4x9a4+11a2b2+4b4（a2-5b2)2+(4ab)2a2-2a+4b-4b2
-
1) 5a-2b+3b-4a-1 a= -1 b=2 (2)7x²-3x²-2x-2x²=
-
已知A=4x²-1/3x+1,B=3x²+2/3x-4,求5A-3B-[5A-(A+2B)]
-
1.b/a-b+1/a 2.（a-2b）平方/ab-（a+2b）平方/ab 3.5-3x/x-2+1-x/2-x 4.x
-
a=x2-2x2+x-4 b=2x3+5x-4 c=-4x2+x-1,2a-(b+c)=?
-
计算：-3x+(x-1)-(3x-3)= 2(a-2)-3(a+1)= -(5a-4b)+2(a-2b)=
-
4a＾2+4ab+b＾2-1((x＾2+1)＾2-x＾2)/(x＾2+x+1) (a＾4-b＾2)/(a+b) (x＾4
-
(1)a(b-3)^2-4(b-3)^2,其中a=5,b=7 (2)4x(m-2)-5（m-2),其中x=1.5,m=2
-
因式分解（x*x+1)(x*x+1)-(4a+10b)(x*x+1)+(2a+5b)(2a+5b)
-
2x-4/(x^2-4x-5)=A/(x-5)+B/(x+1),x≠5,-1.A.B的值是