f(x+2)=1/f(x),f(1)=-5
所以f(1+2)=1/f(1) =>f(3)=-1/5
f(5)=f(3+2)=1/f(3)=-5
f(x+2)=1/f(x) =>f(x)=1/f(x+2)
F[f(5)]=F(-5)=1/f(-5+2)=1/f(-3)=f(-3+2)=f(-1)=1/f(-1+2)=1/f(1)=-1/5
仔细点看下公式的变换,应该明白了!
f(x+2)=1/f(x),f(1)=-5
所以f(1+2)=1/f(1) =>f(3)=-1/5
f(5)=f(3+2)=1/f(3)=-5
f(x+2)=1/f(x) =>f(x)=1/f(x+2)
F[f(5)]=F(-5)=1/f(-5+2)=1/f(-3)=f(-3+2)=f(-1)=1/f(-1+2)=1/f(1)=-1/5
仔细点看下公式的变换,应该明白了!