a3+b5=1+2d+q^4=21
2d+q^4=20
a5+b3=1+4d+q^2=13
4d+q^2=12
4d+2q^4=40
2q^4-q^2=38求解q 再回带求解带入找an /bn规律 再求和
已知{an}是等差数列,{bn}是各项都为正数的等比数列,a1=b1=1,a3+b5=21,a5+b3=13 求数列{a
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