Lim(x→无穷大)√(x^2+3x)-x
1个回答
lim(x→inf.)[√(x^2+3x) - x]
= lim(x→inf.)3x/[√(x^2+3x) + x]
= lim(x→inf.)3/[√(1+3/x) + 1]
= 3/2
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