Question

已知函数f(x)=log小a 1-mx/x-1(a大于1)的图像关于圆点对称

Answer 1

f(x)关于原点对称

f(x)=-f(-x)

loga[(1-mx)/(x-1)]=-loga[(1+mx)/(-x-1)]

(1-mx)/(x-1)=(-x-1)/(1+mx)

(1-mx)(1+mx)=-(x+1)(x-1)

1-(mx)^2=1-x^2

(m^2-1)x^2=0

m=±1

因为：m=1时,[(1-mx)/(x-1)]=-1