计算0.064^(-1/3)-(-7/8)^0+[(-2)^3]^(-4/3)+16^(-0.75)+0.01^(1/2
1个回答
0.064^(-1/3)-(-7/8)^0+[(-2)^3]^(-4/3)+16^(-0.75)+0.01^(1/2)
=2.5-1+1/16+1/8+0.1
=1.7875
相关问题
0.064^(-1/3)-1+16^0.75+0.01^(1/2)
(0.064)∧(-1/3)+[(-2)3]∧(-4/3)+16^(-0.75)=?
0.064^-1/3-(-1/8)^0+7log7^2+0.25^2/5·0.5^-4
比较下列各题中两个数的大小:(1)3^0.8,3^0.7(2)0.75^-0.1,0.75^0.1(3)1.01^2.7
原式=0.064^(-1/3)-(-1/8)^0+16^3/4+0.25^1/2+2log3(6)-log3(12) 那
(1)计算(1/0.064)1/3-(-7/80)+160.75+0.251/2 (2)若log23=a,log52=b
规律填数 (1)6.25 2.5 1 ____ ____ 0.064 (2)7 3.5 1.75 ____ ____ 0
口算:0.125×16= 3-1.06= 0.6÷6= 16.8-7= 1.01×0.2×0.1= 11-1 2 3 =
用简便方法计算下面各题0.98-0.036-0.064 8.57×103-8.57×3 1.01×1.01-1.01