AM AN =(x1+2,y1)(x2+2,y2)
=x1x2+2(x1+x2)+y1y2+4
M,N均在直线x=ky-6/5上,则:
x1=ky1-6/5
x2=ky2-6/5
可得:x1x2=k²y1y2-(6/5)k(y1+y2)+36/25
x1+x2=k(y1+y2)-12/5
所以,AM AN=x1x2+2(x1+x2)+y1y2+4
=(k²+1)y1y2+(4/5)k(y1+y2)+16/25
ps:你4/5后面漏了一个k
AM AN =(x1+2,y1)(x2+2,y2)
=x1x2+2(x1+x2)+y1y2+4
M,N均在直线x=ky-6/5上,则:
x1=ky1-6/5
x2=ky2-6/5
可得:x1x2=k²y1y2-(6/5)k(y1+y2)+36/25
x1+x2=k(y1+y2)-12/5
所以,AM AN=x1x2+2(x1+x2)+y1y2+4
=(k²+1)y1y2+(4/5)k(y1+y2)+16/25
ps:你4/5后面漏了一个k